Showing posts with label exponential equations in quadratic form. Show all posts
Showing posts with label exponential equations in quadratic form. Show all posts

Wednesday, February 12, 2014

3.4 Solving Exponential and Logarithmic Equations

There are 2 main methods you can use to solve equations involving exponential and logarithmic functions:

1) The “Key to Everything”

This states that:  if and only if 

This is the definition of a logarithm.


2) The One-to-One Property

This states that when  and :

 if and only if 
 if and only if 

This property works because exponential and logarithmic functions are one-to-one, meaning that for every x value, there is only one corresponding y value. In other words, they pass the vertical line test.

To illustrate the one-to-one property:
If , we can conclude that x=3.

It is also helpful to know the Inverse Properties of logarithms:


     We can show that this is true using the key to everything. 
     Rearranging the above equation, we find that:

 
     Again, the key to everything helps us prove this. Rearranging the equation, we see that:

Knowing all the other properties of logarithms, which can be found in the post on section 3.3, will also be very useful in solving such equations.



Examples:

Solving Exponential Equations  
1)  Solve for x.


     Given this equation, we can simplify the right side:
 
 
     Using the one-to-one property, we can then conclude that x=-5.



2)  Solve for x.


    Using the key to everything, we find that:

    Since a logarithm with a base of “e” is the same as a natural log, we simplify to:

    The answer can be written as x=ln3, which is approximately equal to 1.099.


Solving Exponential Equations in Quadratic Form
3) Solve .

    First, we substitute in  to get:
    Then, we factor and solve like a regular quadratic:
 and
    Next, we substitute again:
and
    Finally, using the key to everything, we find that: 
and *

    *HOWEVER: The solution x=ln(-2) is extraneous, because you cannot take the logarithm or the natural logarithm of a negative number. Therefore, the only real solution to this equation is x=ln5.


Solving Logarithmic Equations
4) Solve .

    Using the one-to-one property, we can simplify to: 

    Then, solve for x as you would normally.




5) Solve .


    We begin by simplifying:
    Then, using the key to everything, we find that:
    We can then solve for x.